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6x^2-8=4x^2+7x
We move all terms to the left:
6x^2-8-(4x^2+7x)=0
We get rid of parentheses
6x^2-4x^2-7x-8=0
We add all the numbers together, and all the variables
2x^2-7x-8=0
a = 2; b = -7; c = -8;
Δ = b2-4ac
Δ = -72-4·2·(-8)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{113}}{2*2}=\frac{7-\sqrt{113}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{113}}{2*2}=\frac{7+\sqrt{113}}{4} $
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